Integers from 1 through 100 are written on a hundred cards. The deck is properly shuffled, and 3 cards are drawn at random.

What is the probability that the cards are drawn in increasing order?

$\frac{3}{100}$
$\frac{1}{8}$
$\frac{1}{3}$
$\frac{ 1}{6}$

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For any $3$ cards there are $3! = 6$ orders in which they can be picked, only one of which is in ascending order. Since each of these orders is equally likely, the desired probability is $\boxed{\dfrac{1}{6}}$ .