Here we have three unit circles, each of which intersect the three vertices of a scalene triangle.

What is the sum of the lengths of the part of the circles that are within the triangle?

Provide your answer to 2 decimal places.

If you think there isn't enough information, submit -1 as your answer.

The answer is 6.28.

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The sum of the angles of the triangle is $180^\circ$ .

So, the sum of the red angles in the picture will be $360^\circ$ since each will be twice as large as the corresponding black corner in the same circle since an inscribed angle in a circle is $\frac{1}{2}$ of the intercepted arc.

Therefore, the sum of the three purple lengths inside the triangle will be:

$2\pi = \boxed{6.28}$ to 2 decimal places.