A gas jar contains three different gass $A, B, C$ . Let $p_i$ and $x_i$ denote the partial pressure and the mole fraction of a gas, respectively. Given that

$p_A+p_B=3625 \text{ Pa}$

$x_A+x_C=0.75$

$x_A=x_B,$

what is the total pressure of the gas mixture in the gas jar in
**
Pascals
**
?

The answer is 7250.

**
This section requires Javascript.
**

You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.

Note that,

$p_i=x_ip$

So the first equation can be written as

$(x_A+x_B)p=3625$

The sum of the mole fractions of components is always $1$ , so from the second equation, we have

$x_B=0.25$

Substitute the value and an additional information that $x_A=x_B$ into the first equation, we get

$(0.25+0.25)p=3625$

$p=7250 \text{Pa}$