216
600
3125
240

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For a number to be divisible by 3, its sum of digits should be divisible by 3. For a five digit number, with the above choices, the number can be made by only excluding either 3 or 0. (0+1+2+3+4+5=15, 15-0=15, 15-3=12)

Excluding 0, numbers possible = 5! =120

Excluding 3, 0 cannot be used as the first digit, hence numbers possible = 4x4x3x2x1=96 Total =120+96=

216