The incenter I of the triangle P Q R is the foot of the normal from the point M = ( 1 , 2 , 6 ) to the x y -plane, where P , Q , R are the feet of altitudes of an isosceles triangle A B C whose vertex is A and base B C of 6 unit length.
Let A → 2 π + lim 1 − sin A e v − e k = L e k for integer k , where v is the volume of the tetrahedron M I B C .
Find the value of k 2 L 2 1 .
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Δ P Q R is the pedal triangle of Δ A B C . Incentre of the pedal triangle is the orthocentre of triangle Δ A B C . I don't see why ' I is the same for Δ P Q R and Δ A B C . Also,I think u need to mention that Δ A B C is in the xy plane .
Though the answer is correct . But I think there is a major flaw in the solution . Area of IBC is not equal to 1/3 area ABC as this triangle is not equilateral.
@Md Zuhair @Thomas Jacob @Aaron Jerry Ninan What do you guys think? Tell me if I am wrong.
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This is a solution by my friend
@Devansh Jain .