3D Pythagorean Theorem

Geometry Level 2

As you can see the dimensions in the figure, you have to calculate the line segment d d . Solve to the tenth only.

Image Credit: http://www.resourceaholic.com/2014/09/pythagoras.html


The answer is 19.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Sam Bealing
May 25, 2016

By Pythagoras' Theorem our answer is:

6 2 + 1 0 2 + 1 6 2 = 361 = 19 \sqrt{6^2+10^2+16^2}=\sqrt{361}=\boxed{19}

I noticed this during the 1st time I was taught the long way this is so much quicker and easier.

Phoebe Shobe - 2 years, 9 months ago
Abdullah Mahmood
May 24, 2016

First calculate the length of line segment a a , which is:

a 2 = 1 0 2 + 6 2 a = 136 a^2=10^2+6^2 \\ \Rightarrow a=\sqrt{136}

Now, again using the pythogoras theorem, we have d 2 = 1 5 2 + a 2 d 2 = 225 + 136 d = 19. d^2=15^2+a^2 \\ \Rightarrow d^2=225+136 \\ \Rightarrow d=19. \square

Please don't write your text in all the capital letters. I've edited your solution. Thanks!

Sandeep Bhardwaj - 5 years ago

Log in to reply

no the solution is wrong

Abdullah Mahmood - 5 years ago

Log in to reply

Can you explain what's wrong?

Sandeep Bhardwaj - 5 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...