4 distinct reals

Algebra Level 2

a 2 + b 2 + c 2 + d 2 = a b + b c + c d + d a \large{a^2+b^2+c^2+d^2=ab+bc+cd+da} Do there exist distinct reals a , b , c , d a,b,c,d which satisfy the above equation?

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1 solution

Sathvik Acharya
Apr 27, 2019

Multiplying by 2, we have 2 ( a 2 + b 2 + c 2 + d 2 ) 2 ( a b + b c + c d + d a ) = 0. 2(a^2+b^2+c^2+d^2)-2(ab+bc+cd+da)=0. Group the terms to get ( a 2 2 a b + b 2 ) + ( b 2 2 b c + c 2 ) + ( c 2 2 c d + d 2 ) + ( d 2 2 d a + a 2 ) = 0. (a^2-2ab+b^2)+(b^2-2bc+c^2)+(c^2-2cd+d^2)+(d^2-2da+a^2)=0. Note that all the terms are squares. Thus the equation can be written as ( a b ) 2 + ( b c ) 2 + ( c d ) 2 + ( d a ) 2 = 0 a b = b c = c d = d a = 0. (a-b)^2+(b-c)^2+(c-d)^2+(d-a)^2=0 \implies a-b=b-c=c-d=d-a=0. This implies that a = b = c = d a=b=c=d , contradicting the fact that a , b , c , d a,b,c,d are distinct .

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