The sum of the first 50 odd natural numbers is equal to $\text{\_\_\_\_\_\_\_\_\_\_}$ .

The answer is 2500.

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$\large \displaystyle \text{Sum of n off natural numbers } 1,3,5,...... (2n-1).\\ \large \displaystyle \implies \sum_{i=1}^n (2n-1) = 2 \times \frac{n(n+1)}{2} - n = n^2 + n - n = n^2.\\ \large \displaystyle \text{Sum of odd numbers is } n^2 \\ \large \displaystyle \text{Sum of first 50 Odd numbers } = n^2 = 50^2 = \color{#D61F06}{\boxed{2500}}.$