If the 8 th term of an arithmetic progression is twice its 6 th term, what is the 4 th term of the arithmetic progression?
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a 8 = 2 ( a 6 )
a 1 + 7 d = 2 ( a 1 + 5 d )
a 1 + 7 d = 2 a 1 + 1 0 d
a 1 = − 3 d
a 4 = a 1 + 3 d = − 3 d + 3 d = 0
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Let the initial term and the common difference of the AP be "a" and "d" respectively. Eighth term of an AP is a + 7d and its sixth term is a + 5d
a + 7d = 2*(a+5d) = 2a + 10d
a = - 3d -----(1)
Fourth term = a + 3d = 0 from (1)