It is observed that for any square of integer that ends with 5, the answer would be an integer that ends with 25. For examples: and .
Assuming the integer before 5 (on the LHS of equation) is assigned as , and the integer before 25 (on the RHS of equation) is . Find function .
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General equation would be:
(10x + 5)^2 = [100 * f(x)] + 25;
Expanding LHS:
(10x + 5)^2 = 100x^2 + 100x + 25 = 100 * (x^2 + x) + 25
Thus, f(x) = (x^2 + x) = x (x+1).