5 - 25 pattern

Algebra Level 2

It is observed that for any square of integer that ends with 5, the answer would be an integer that ends with 25. For examples: 1 5 2 = 225 15^2 = 225 and 2 5 2 = 625 25^2 = 625 .

Assuming the integer before 5 (on the LHS of equation) is assigned as x x , and the integer before 25 (on the RHS of equation) is f ( x ) f(x) . Find function f ( x ) f(x) .

f ( x ) = x ( x + 1 ) f(x) = x (x + 1) f ( x ) = 4 x 2 f(x) = 4x - 2 f ( x ) = 10 x 4 x f(x) = 10x - \frac 4x f ( x ) = 2 x 3 x f(x) = 2x^3 - x

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1 solution

Cl Chong
Jun 15, 2018

General equation would be:

(10x + 5)^2 = [100 * f(x)] + 25;

Expanding LHS:

(10x + 5)^2 = 100x^2 + 100x + 25 = 100 * (x^2 + x) + 25

Thus, f(x) = (x^2 + x) = x (x+1).

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