The answer is 3750.

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As according to basic number theory ;if any number $m$ has $2$ prime factors f1 , f2 raised to the power $a, b$ given by $m=f1^a*f2^b$ then

numberof factors of $m =(a+1)*(b+1)$ .applying the same thing in the given question ;(according to the given condition ) $N=(p1)^5*(p2)^a*(p3)^b*(p4)^c*(p5)^d$

$=>6*5^4=3750$ ANSWER