Let N be a number which has 5 prime factors . One of the prime factor's power is 5 and rest of the prime factors' power are less than 5 . What is the maximum number of divisors N can have ?
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As according to basic number theory ;if any number m has 2 prime factors f1 , f2 raised to the power a , b given by m = f 1 a ∗ f 2 b then number of factors of m = ( a + 1 ) ∗ ( b + 1 ) .
applying the same thing in the given question ;(according to the given condition ) N = ( p 1 ) 5 ∗ ( p 2 ) a ∗ ( p 3 ) b ∗ ( p 4 ) c ∗ ( p 5 ) d
= > 6 ∗ 5 4 = 3 7 5 0 ANSWER