Five pipes of equal radius carry air into a sixth pipe with a radius ten times larger. If the air moves with speed in the larger pipe. How many times larger than is the speed of air in one of the smaller pipes?
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Since there are five pipes of equal radius initially, the continuity equation can be written
5 A 1 v 1 = A 2 v 2 .
The problem gives r 2 = 1 0 r 1 , so
5 π r 1 2 v 1 = π ( 1 0 r 1 ) 2 v
5 r 1 2 v 1 = 1 0 0 r 1 2 v
v 1 = 2 0 v .