50% Orange Juice

Algebra Level 2

How much (in gallons) of a 70% orange juice drink must be mixed with 44 gallons of 20% orange juice drink to obtain a mixture that is 50% orange juice ?

48 56 72 66

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2 solutions

Saya Suka
Mar 5, 2021

20% have to go up 30% to reach 50% while 70% have to go down 20% to reach 50% as the intended concentration. So 70% have to work the 30% upwards efforts (50% - 20%) while 20% have to work the 20% downwards efforts (70% - 50%). 30% : 20% = 3 : 2 must be the ratio of volumes, so :

Answer = 3 × 44 / 2 = 66 gallons

Ron Gallagher
Mar 5, 2021

Let x = the number of gallons of 70% juice added to the mixture. Then, the total amount of liquid after adding the juice is 44 + x. Also, the total amount of pure orange juice is .20 (44) + .70 x. Since the proportion of juice must be 1/2, we find:

(.2 44 + .7 x) / (44 + x) = 1/2

Solving this equation for x yields x = 66

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