The sequence:
Where each term, after the first, is more than times the previous term. For what value of will the term be a multiple of ?
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The n-th term can be written as Un = 10^(n-1) x + 777...7 (n-1) digit So U50 = 10^49 (x) + 77777....7. If the number can be divided by 9, the sum of the digit must be divisible by 9. The sum of the digit is 7 (49) + x. So x=8.