50 terms are bad enough, but this?!?!

Level pending

The sequence: x , 10 x + 7 , 10 ( 10 x + 7 ) + 7 , 10 ( 10 ( 10 x + 7 ) + 7 ) + 7 , . . . . x,10x+7,10(10x+7)+7,10(10(10x+7)+7)+7,.... 1 < x < 9 1<x<9

Where each term, after the first, is 7 7 more than 10 10 times the previous term. For what value of x x will the 50 t h 50th term be a multiple of 9 9 ?


The answer is 8.

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1 solution

Ruslan Abdulgani
Jan 21, 2015

The n-th term can be written as Un = 10^(n-1) x + 777...7 (n-1) digit So U50 = 10^49 (x) + 77777....7. If the number can be divided by 9, the sum of the digit must be divisible by 9. The sum of the digit is 7 (49) + x. So x=8.

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