Suppose I have a deck of 52 cards, and 51 of those cards were queens, while the remaining card is a Joker. If I were to arrange all of these cards at random, what's the probability (in percentage) that all of the 51 queens will be side-by-side?

(Round your answer to the nearest whole number)

The answer is 4.

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\[\begin{align} \text{Total arrangements} &= 52 \quad [\color{blue}{\text{The number of unique places to place joker}}] \\ \text{Probable outcomes} &= 2 \quad [\color{blue}{\text{When joker is either first or last}}]

\end{align}\]

$\text{Probability } = \dfrac{\text{Probable outcomes}}{\text{Total arrangements}} = \dfrac{2}{52} \approx \boxed{4\%}$