52nd Problem 2016

Geometry Level 2

cos θ csc θ sin θ sec θ = ? \large \dfrac { \cos { \theta -\csc { \theta } } }{ \sin { \theta } -\sec { \theta } } =?


Check out the set: 2016 Problems

tan θ \tan\theta 2 tan 2 θ 2\tan ^{ 2 }{ \theta } cot 2 θ \cot^{ 2 }\theta cot θ \cot\theta

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1 solution

Marta Reece
Jul 19, 2017

cos θ csc θ sin θ sec θ = ( sin θ cos θ 1 ) 1 sin θ ( sin θ cos θ 1 ) 1 cos θ = cos θ s i n θ = cot θ \dfrac { \cos { \theta -\csc { \theta } } }{ \sin { \theta } -\sec { \theta } }=\dfrac{(\sin\theta\cos\theta-1)\frac1{\sin\theta}}{(\sin\theta\cos\theta-1)\frac1{\cos\theta}}=\dfrac{\cos\theta}{sin\theta}=\cot\theta

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