$\displaystyle \frac { \cos { \theta } }{ 1+\sin { \theta } } +\frac { 1+\sin { \theta } }{ \cos { \theta } } =?$

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Check out the set:
2016 Problems
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$2\cos\theta$
$2\sec { \theta }$
$\sec { \theta }$
1

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$\begin{aligned} \frac{\cos \theta}{1+ \sin \theta} + \frac{1 + \sin \theta}{\cos \theta} & = \frac{\cos^2 \theta + (1 + \sin \theta)^2}{(1 + \sin \theta)\cos \theta} \\ & = \frac{\cos^2 \theta + \sin^2 \theta + 1 + 2\sin \theta}{(1 + \sin \theta)\cos \theta} \\ & = \frac{2 + 2\sin \theta}{(1 + \sin \theta)\cos \theta}\\ & = \frac{2(1 + \sin \theta)}{(1 + \sin \theta)\cos \theta} \\ & = \frac 2{\cos \theta} \\ & = \frac 2{\frac 1{\sec \theta}} \\ & = 2 \sec \theta \end{aligned}$