Level
pending

$a+b+c=1$

$a^2+b^2+c^2=2$

$a^3+b^3+c^3=3$

$a^5+b^5+c^5=?$

The answer is 6.

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It's just simple Equation Solving Problem. = ( a^2 + b^2 + c^2 ) * (a^3 + b^3 + c^3) = a^5 + b^5 + c^5 + a^3(2 - a^2) + b^3(2 - b^2) + c^3(2 - c^2) now on cancelling power(5) = 2( a^3 + b^3 + c^3) = 2 * 3 = 6

:: sorry man, I tried with Latex