6 digit number

a a a a a a = b c × b c ( 2 c b ) ( 2 b + c ) ( c b ) \large\overline{aaaaaa}=\overline{bc} \times b c (2c-b) (2b+c) ( c-b)

If natural numbers a , b , c a,b,c satisfy the above equation , find the product a b c abc .


Details And Assumptions:

  • b c \overline{bc} is a two digit number and a a a a a a \overline{aaaaaa} is a six digit number.


The answer is 84.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Azzim Habibie
Dec 21, 2015

we can write the LHS as 111111a, 111111a = 3×7×11×13×37×a then we put b = 3 and c = 7. Finally we got a = 4. So, abc = 4.3.7 = 84

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...