Six identical resistors of resistance $6\ \Omega$ each are to be connected across terminals $A$ and $B$ . Over all the arrangements of the resistors, what is the minimum current $i_{\text{min}}$ (in Amperes) that can flow through the ammeter?

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Note:
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All elements in the circuit are ideal.

$6$
$\frac{1}{36}$
$\frac{1}{6}$
$1$
None of these choices
$36$

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Current in the circuit will be minimum when Resistance of the circuit is maximum and that's the Case when all six $6\ \Omega$ resistors are connected in series to give $R_{\text{net}}=36\ \Omega$ .

$\Large \therefore i_{\text{min}}=\dfrac{V}{R_{\text{net}}}=\boxed{\color{#007fff}{\dfrac{1}{6}}}$