67th Problem 2016

Algebra Level 3

[ 6 × ( 5 ! ) + ( 4 2 ) 4 2 + ( 5 ) 2 × 7 ] + 19 ÷ 5 = ? \left[ 6\times \left( -5! \right) +\left( { -4 }^{ 2 } \right) -{ 4 }^{ 2 }+\left( -5 \right) ^{ 2 }\times 7 \right] +19\div 5\quad =\quad ?


Check out the set: 2016 Problems


The answer is -573.2.

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1 solution

Angela Fajardo
Mar 23, 2016

[ 6 × ( 5 ! ) + ( 4 2 ) 4 2 + ( 5 ) 2 × 7 ] + 19 ÷ 5 = ? = [ 6 × ( 120 ) + ( 16 ) 16 + 25 × 7 ] + 19 ÷ 5 = [ ( 720 ) + ( 16 ) 16 + 175 ] + 19 ÷ 5 = [ ( 736 ) 16 + 175 ] + 19 ÷ 5 = [ ( 752 ) + 175 ] + 19 ÷ 5 = ( 577 ) + 19 ÷ 5 = ( 577 ) + 3.8 = 573.2 \left[ 6\times \left( -5! \right) +\left( { -4 }^{ 2 } \right) -{ 4 }^{ 2 }+\left( -5 \right) ^{ 2 }\times 7 \right] +19\div 5\quad =\quad ?\\ =\quad \left[ 6\times \left( -120 \right) +\left( { - }16 \right) -16+25\times 7 \right] +19\div 5\\ =\quad \left[ (-720 \right) +\left( { - }16 \right) -16+175]+19\div 5\\ =\quad \left[ (-736 \right) -16+175]+19\div 5\\ =\quad \left[ (-752 \right) +175]+19\div 5\\ =\quad \left( -577 \right) +19\div 5\\ =\quad \left( -577 \right) +3.8\\ =\quad \boxed { -573.2 }

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