68th Problem 2016

Algebra Level 1

( 1 2 ) 8 × 4 2 = ? \huge\left(\dfrac 12\right)^{-8}\times 4^{-2} \ = \ ?


Check out the set: 2016 Problems


The answer is 16.

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1 solution

Angela Fajardo
Mar 23, 2016

( 1 2 ) 8 × 4 2 = ? = ( 2 ) 8 × ( 1 4 ) 2 = 256 × ( 1 16 ) = 16 \LARGE \left( \frac { 1 }{ 2 } \right) ^{ -8 }\times { 4 }^{ -2 }\quad =\quad ?\\ =\quad \left( 2 \right) ^{ 8 }\times \left( \frac { 1 }{ 4 } \right) ^{ 2 }\\ =\quad 256\times \left( \frac { 1 }{ 16 } \right) \\ =\quad \boxed { 16 }

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