$\large \int _{ 1 }^{ 4 }{ { x }^{ 2 }dx } = ?$

The answer is 21.

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$\int { { x }^{ 2 }dx } =\frac{x^3}3+C$

$\int _{ 1 }^{ 4 }{ { x }^{ 2 }dx } =\frac{4^3}3-\frac{1^3}3=21$