N is an integer whose representation in base b is 777. Find the smallest positive integer b for which N is the fourth power of an integer.
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How did you conclude its 7?, i didn't get it.
Good solution (I did it by brute force, translating 777 in various bases into base 10 until I had a number that I knew was a fourth power - I am good at rapid fire calculations, so it did not take l.ong)
We have 7 b 2 + 7 b + 7 = k 4 or 7 ( b 2 + b + 1 ) = k 4 then 7 ∣ k 4 → 7 ∣ k
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Sorry for the long and convoluted solution...
Let N = k 4 for some positive integer k . Then, we get 7 b 2 + 7 b + 7 = k 4 7 ( b 2 + b + 1 ) = k 4 k 4 has 7 as a factor, so is of a form 7 4 ∗ x 4 = > 7 4 ∗ x 4 = 7 ( b 2 + b + 1 ) = > 7 3 ∣ ( b 2 + b + 1 ) = > ( 7 3 − 1 ) ∣ b ( b + 1 ) = > 3 4 2 ∣ b ( b + 1 ) By observation, 3 4 2 = 1 8 ∗ 1 9 so we have b = 1 8
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Let N = k 4 for some positive integer k . Then, we get 7 b 2 + 7 b + 7 = k 4 7 ∣ k 4 ⇒ 7 ∣ k Substituting in k = 7 , we get the answer b = 1 8 . (You can check the discriminant as well, but I left it out.)