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Calculus Level 5

n = 1 ( 1 ) n ( H n ln ( n + 2 x ) γ ) = γ a ln ( ( 2 x 1 ) ! ! π b c x x ! ) \displaystyle\sum _{ n=1 }^{ \infty }{ { (-1) }^{ n }({ H }_{ n }-\ln { (n+2x) } -\gamma ) } =\dfrac { \gamma }{ a } -\ln { \left( \dfrac { (2x-1)!!\sqrt [ b ]{ \pi } }{ { c }^{ x }x! } \right) } If the equation above is true for positive integers a a , b b , c c and x x , find a + b + c a+b+c .

Notations :

  • H n = 1 + 1 2 + 1 3 + + 1 n H_n = 1 + \dfrac12 + \dfrac13 + \cdots + \dfrac1n is the n th n^\text{th} harmonic number .
  • γ 0.5772 \gamma \approx 0.5772 is the Euler-Mascheroni constant .
  • ! ! !! denotes the double factorials function.


The answer is 6.

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