If you are given 8 queens and you have to place them in a regular $8\times 8$ chessboard in a manner such that none of them is attacking each other. In how many ways you can keep them.

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Note
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: If you find a way out, then try re-arranging the same in different places. Use the image.

The answer is 92.

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Chess composer Max Bezzel published the eight queens puzzle in 1848. Franz Nauck published the first solutions in 1850. Nauck also extended the puzzle to the n queens problem, with n queens on a chessboard of n × n squares.

SolutionsThe eight queens puzzle has 92

distinctsolutions. If solutions that differ only by symmetry operations (rotations and reflections) of the board are counted as one, the puzzle has 12fundamentalsolutions.A fundamental solution usually has eight variants (including its original form) obtained by rotating 90, 180, or 270° and then reflecting each of the four rotational variants in a mirror in a fixed position. However, should a solution be equivalent to its own 90° rotation (as happens to one solution with five queens on a 5x5 board), that fundamental solution will have only two variants (itself and its reflection). Should a solution be equivalent to its own 180° rotation (but not to its 90° rotation), it will have four variants (itself and its reflection, its 90° rotation and the reflection of that). It is not possible for a solution to be equivalent to its own reflection (except at n=1) because that would require two queens to be facing each other.

Of the 12 fundamental solutions to the problem with eight queens on an 8x8 board, exactly one is equal to its own 180° rotation, and none is equal to its 90° rotation; thus, the number of distinct solutions is $11\cdot8 + 1\cdot4 = 92$ (where the 8 is derived from four 90° rotational positions and their reflections, and the 4 is derived from two 180° rotational positions and their reflections)