80th Problem 2016

$\large{\text{Let:}}$

$\large{{ a }_{ 1 }=15000}$

$\large{d=2000}$

$\large{n=(2017-2000)+1 =18}$

$\large{\text{Solution:}}$

$\large{a_{ n }=a_{ 1 }+(n-1)d\\ \quad =15000+(17)(2000)\\ \quad = 49000}$

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$\large{\therefore \text{His annual salary in } 2017 \text{ will be } \$49000}$