Grazing Grass

Algebra Level 1

9 cows ate 9 fields of grass in 9 hours.

How long does it take (in hours) for 3 cows to eat 3 fields of grass?

(Assume that all cows eat grass at the same constant rate.)

3 6 9 12

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

J D
Jun 3, 2016

Relevant wiki: Ratio, Rate and Proportion - Problem Solving

Nine cows eat 1 field/hr. So three cows eat 1/3 field/hr. So in nine hours they can eat three fields, and 9:3 = 3:1

Charles Z
Aug 22, 2020

Since we are given 9 cows eat 9 fields in 9 hours, we have the equation 9 c 9 f = 9 h \frac{9c}{9f} = 9h (where c stands for cows, f stands for fields, and h stands for hours). After simplification, we have that c f = 9 h \frac{c}{f} = 9h . So, to find the time for 3 cows to eat 3 fields, we multiply both the denominator and the numerator by 3, to get c × 3 f × 3 = 3 c 3 f = 9 h \frac{c \times 3}{f \times 3} = \frac{3c}{3f} = 9h . So 3 cows eat 3 fields in 9 hours.

Viki Zeta
Jun 4, 2016

You can also apply, direct proportion here.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...