97th Problem 2016

Algebra Level 1

Evaluate:

$\large 0!\times \left(\dfrac{\dfrac 12}{{2}^{-1}}\right)^{ 0! } \ = \ ?$

1 solution

Angela Fajardo
Mar 26, 2016

Since $0!=1$

$\LARGE \frac { \frac { 1 }{ 2 } }{ { 2 }^{ -1 } } =?$

=> $\LARGE \frac { { 2 }^{ -1 } }{ { 2 }^{ -1 } } =1$

=> $\LARGE \frac { \frac { 1 }{ 2 } }{ \frac { 1 }{ 2 } } =1$

Same technique..

Sagar Shah - 5 years, 2 months ago