99999

There is a function defined in the following way: $f\left( n \right) = 0.99.....99$ so that the number of 9s in the number $f\left( n \right)$ is $n$ .

If that is the case, how many number 9s has the following number $r = f\left( 1000 \right) \times f\left( 1000 \right)$ ?

Link for question