How many of those in the following are possible to complete with
ANY
operation in between the three digits in the left-hand side? Answer with a number.
_
0
_
0
_
0
_
_
1
_
1
_
1
_
_
2
_
2
_
2
_
_
3
_
3
_
3
_
_
4
_
4
_
4
_
_
5
_
5
_
5
_
_
6
_
6
_
6
_
_
7
_
7
_
7
_
_
8
_
8
_
8
_
_
9
_
9
_
9
_
=
6
=
6
=
6
=
6
=
6
=
6
=
6
=
6
=
6
=
6
Operations include brackets and others.
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Precisely how I did it!
There are multiple ways to answer each question, so all 10 are possible:
( 0 ! + 0 ! + 0 ! ) ! ( 1 + 1 + 1 ) ! 2 + 2 + 2 3 × 3 − 3 4 + 4 + 4 5 + 5 ÷ 5 6 + 6 − 6 7 − 7 ÷ 7 8 − 8 + 8 ( 9 − ( 9 + 9 ) ) ! = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6
Notation: ! denotes the factorial notation . For example: 8 ! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 .
The sqrt means square root (there was an error in the post)
@ll T.O.P ll §Mart , you need to put \ ( \ ) or \ [ \ ] to effect the LaTex code. I have edited your solution. Take a look.
Thank you for fixing it.
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All 1 0 are possible:
( 0 ! + 0 ! + 0 ! ) ! ( 1 + 1 + 1 ) ! 2 + 2 + 2 3 × 3 − 3 4 + 4 + 4 5 ÷ 5 + 5 6 + 6 − 6 7 − 7 ÷ 7 ( 8 ÷ 8 + 8 ) ! ( 9 + 9 − 9 ) ! = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6
Notation: ! denotes the factorial notation . For example: 8 ! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 .