How many of those in the following are possible to complete with
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ANY
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operation in between the three digits in the left-hand side? Answer with a number.

$\begin{aligned} \_ 0\_ 0\_ 0\_ & = 6 \\ \_ 1\_ 1\_ 1\_ & = 6 \\ \_ 2\_ 2\_ 2\_ & = 6 \\ \_ 3\_ 3\_ 3\_ & = 6 \\ \_ 4\_ 4\_ 4\_ & = 6 \\ \_ 5\_ 5\_ 5\_ & = 6 \\ \_ 6\_ 6\_ 6\_ & = 6 \\ \_ 7\_ 7\_ 7\_ & = 6 \\ \_ 8\_ 8\_ 8\_ & = 6 \\ \_ 9\_ 9\_ 9\_ & = 6 \end{aligned}$

Operations include brackets and others.

The answer is 10.

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All $\boxed {10}$ are possible:

$\begin{aligned} (0!+0!+0!)! & = 6 \\ (1+1+1)! & = 6 \\ 2+2+2 & = 6 \\ 3 \times 3 - 3 & = 6 \\ \sqrt 4 + \sqrt 4 + \sqrt 4 & = 6 \\ 5 \div 5 + 5 & = 6 \\ 6+6-6 & = 6 \\ 7 - 7 \div 7 & = 6 \\ \left(\sqrt {8 \div 8 + 8}\right)! & = 6 \\ \left(\sqrt {9+9-9}\right)! & = 6 \end{aligned}$

Notation:$!$ denotes the factorial notation . For example: $8! = 1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8$ .