A 5-th order equation

Level 2

The real root of the equation x 5 + x 4 + 2 x 3 + 2 x 2 + x + 0.2 = 0 x^5+x^4+2x^3+2x^2+x+0.2=0 has the form A 5 + B \sqrt[5]{A} + B , where A , B A, B are integers, find A + B A + B .


The answer is -5.

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1 solution

Aaghaz Mahajan
Apr 10, 2018

Multiply by 5 and see the magic of Binomial theorem!!!

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