A Ninth Grade Inequality

Algebra Level 4

( x 100 ) 4 + ( x 102 ) 4 + 30 ( x 100 ) 2 ( x 102 ) 2 \large (x-100)^4+(x-102)^4+30(x-100)^2(x-102)^2 If x x is a real number larger than 101, then find the minimum value of the expression above.

Let this value be denoted as y y , submit your answer as y y plus the value of x x at this minimum value.

Give your answer to 2 decimal places.


The answer is 115.86.

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1 solution

P C
Feb 23, 2016

Set t = x 101 ; t > 0 t=x-101 ; t>0 , the expression becomes ( t + 1 ) 4 + ( t 1 ) 4 + 30 ( t 1 ) 2 ( t + 1 ) 2 (t+1)^4+(t-1)^4+30(t-1)^2(t+1)^2 = [ ( t + 1 ) 2 ( t 1 ) 2 ] 2 + 32 ( t 2 1 ) 2 = [(t+1)^2-(t-1)^2]^2+32(t^2-1)^2 = 32 t 4 48 t 2 + 32 =32t^4-48t^2+32 = 32 ( t 2 3 4 ) 2 + 14 14 =32\bigg(t^2-\frac{3}{4}\bigg)^2+14\geq 14 So the minimum is 14 14 and the equality holds when x = 101 + 3 2 x=101+\frac{\sqrt{3}}{2} 14 + 101 + 3 2 115.86 \Rightarrow 14+101+\frac{\sqrt{3}}{2}\approx 115.86

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