An algebra problem by Simran Kajal

Algebra Level 1

Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together?

3.65 hours 2.73 hours 2 hours 5.66 hours

Simran Kajal by Simran Kajal , 22

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8 solutions

Yeshah Maka
Mar 3, 2014

We would add the inverse of the time taken and then use the reciprocal as the result . 1/5+1/6= 11/30, now take its reciprocal ie. 30/11. This is your final answer.

6 Helpful 0 Interesting 0 Brilliant 0 Confused

why we are doing inverse this?

Muzna Khan - 7 years, 2 months ago

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We will inverse this because it is a work-time problem. Hence, if a man does a work in 5 hours, he would do 1/5 work in 1 hour. Same for the other. Hence the solution 1/5+1/6=11/30. Therefore, they will complete 11/30th of the work in 1 hour. Hence, they would finish the work in 30/11 hours.

Akshat Mantri - 7 years, 1 month ago
Rahul Vaidya
Mar 2, 2014

this is the problem of time and work...... so if A done work in X hours and B done the same work in Y hours..so in combined they done in X * Y / (X+Y) hours..........

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6*5/6+5=2.7 Ans

Prince Kumar - 7 years, 2 months ago

What

Manav Sethi - 7 years, 2 months ago
Dhananjay Umalkar
Mar 23, 2014

x mws in 1/5 and y mws in 1/6 together they mws 1/5+1/6=11/30=1/2:7272727272 that is 2:73

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Swarali Patil
May 3, 2014

Speed of Jack to mow one garden = 1 Lawn/ 6 hrs
Speed of Marilyn to mow one garden = 1 Lawn/ 5 hrs
Thus, speed with which they work together = 1/5 + 1/6
= 11 lawns /30 Hrs
So, they can mow 1 lawn in 30/11 hrs. Which is 2.73.
Ans: 2.73




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Wilbert Tumaneng
Mar 31, 2014

1/5 + 1/6 = 1/X

11/30 =1/X

X=2.73

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James Hirow
Mar 22, 2014

1/6+1/5=11/30 , thus 11/30=x hour ; x hour = 30/11 => aproc. 2,73 hours.

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Sumitha Sekaran
Mar 21, 2014

A can do 1/6 th of the work in 1 hr. B can do 1/5th of the work in 1 hr. (1/6 + 1/5) = 11/30 . Time taken by them will be 30/11 = 2.73 hrs

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Rushyanth Reddy
Mar 7, 2014

5x6/5+6

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