Find the minimum value of x when it's sum is the least . n varies from 1 to 432.

The answer is 216.

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first of all the problem is incorrectly stated. what it means is: .

find the value of x for which the expression $\sum_{n=1}^{432}$ |x-n| has the minimum possible value.

now simply x=432/2 =216 will give the solution