A beautiful geometric sequence!

Number Theory Level pending

The Sierpinski Triangle involves a sequence of geometric figures. The first figure in the sequence is an equilateral. The second has an inverted (white) equilateral inscribed inside an equilateral triangle as shown. Each subsequent figure in this sequence is obtained by inserting an inverted (white) triangle inside each non-inverted (shaded) triangle of the previous figure. How many regions ( both white and shaded together) are in the tenth figure in this sequence?

For example, the first three figures in the sequence have 1 region, 4 regions and 13 regions respectively.


The answer is 29524.

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2 solutions

Sathvik Acharya
May 19, 2017

Sierpinski triangle

The number of regions is given by the recurrence R ( 1 ) = 1 R(1)=1 , R ( 2 ) = 4 R(2)=4 and R ( n ) = 3 R ( n 1 ) + 1 R(n)=3R(n-1)+1 for n > 1 n>1 . The value of R ( 10 ) R(10) can then be obtained by solving this recurrence or using the formula R ( n ) = 3 n 1 2 R(n)=\dfrac{3^n-1}{2} . The number of regions turns out to be 29524 29524 .

For n = 1 there are 3 0 1 = 1 3^{0-1}=1 regions, for n = 2 there are 3 0 1 + 3 2 1 = 4 3^{0-1} + 3^{2-1}=4 regions and so on. So for the 10th figure that is n = 1 n = 10 3 n 1 = 29524 \sum_{n=1}^{n=10}3^{n-1}=29524 regions.

Sorry, can you edit your solution as it is unclear. How is 3^9=29524? 3^9 is 19683 and 'For n = 0 there are 3^(n-1) regions' does not make sense. Thank you

Sathvik Acharya - 4 years ago

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You are totally right... It has to be summed from n=0 to n=9... Being mobile now editing is hard, I will do it on pc later.

Peter van der Linden - 4 years ago

For n = 0 there are 3 n 1 3^{n-1} regions.

How do you know this is true?

Pi Han Goh - 4 years ago

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It was faulty (see comments below). Should be right now.

Peter van der Linden - 4 years ago

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