If x is a real number satisfying the following equation ∣ ∣ ∣ ∣ 6 x 2 + x − 2 x − 2 ∣ ∣ ∣ ∣ + ∣ 2 − x ∣ = ∣ 6 x 2 + x − 2 ∣ ( x − 2 ) 2 + 1 If the sum of all the values of x can be expressed in the form b a then find the value of a + b
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what a wonderful solution. Keep it up.
Shit. I didn't only have -1. Nice solution
The solution can be obtained by plotting the curve as follows (if it is not considered cheating):
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The given equation can be rewritten as ∣ ∣ ∣ ∣ 6 x 2 + x − 2 x − 2 ∣ ∣ ∣ ∣ + ∣ x − 2 ∣ = ∣ 6 x 2 + x − 2 ∣ ∣ x − 2 ∣ ⋅ ∣ x − 2 ∣ + 1 Let
∣ x − 2 ∣ = a and
∣ ∣ ∣ ∣ 6 x 2 + x − 2 x − 2 ∣ ∣ ∣ ∣ = b
Now the expression can be rewritten in terms of a and b as ⇒ b + a = a b + 1 ⇒ ( a − 1 ) ( b − 1 ) = 0 ⇒ a = 1 , b = 1
∣ x − 2 ∣ = 1 ⇒ x = 1 , 3
∣ ∣ ∣ ∣ 6 x 2 + x − 2 x − 2 ∣ ∣ ∣ ∣ = 1
⇒ 6 x 2 + x − 2 x − 2 = ± 1 ⇒ x = − 1 , 0 , 3 2
⇒ x = − 1 , 0 , 3 2 , 1 , 3