A Big Fraction

Logic Level 2

a 1 = 1 2 = 1 2 , a 2 = 1 2 3 4 = 1 × 4 2 × 3 , a 3 = 1 2 3 4 5 6 7 8 = 1 × 4 × 6 × 7 2 × 3 × 5 × 8 a_{1}=\frac12={\color{#D61F06}\frac12},\qquad a_{2}=\dfrac{\hspace{2mm} \frac12 \hspace{2mm} }{\hspace{2mm} \frac34\hspace{2mm} }={\color{#D61F06}\frac{1\times4}{2\times3}}, \qquad a_{3}=\dfrac{\hspace{2mm} \dfrac{\hspace{2mm} \frac12\hspace{2mm} }{\hspace{2mm} \frac34\hspace{2mm} }\hspace{2mm} }{\dfrac{\hspace{2mm} \frac56\hspace{2mm} }{\hspace{2mm} \frac78\hspace{2mm} }}={\color{#D61F06}\frac{1\times4\times6\times7}{2\times3\times5\times8}} The sequence a n ( n = 1 , 2 , 3 , . . . ) a_n \, (n=1, 2, 3, ...) goes on like the above, forming a really large fraction. Look at the final fractions (red ones), where 1 is always a part of the numerator, 2 a part of the denominator, 3 a part of the denominator ( ( starting from a 3 ) , a_3), and so on: 1 × 4 × 6 × 7 × 10 × 11 × 2 × 3 × 5 × 8 × 9 × 12 × . {\color{#D61F06}\frac{\hspace{2mm} 1\times4\times6\times7\times10\times11\times\cdots\hspace{2mm} }{2\times3\times5\times8\times9\times12\times\cdots}}. Will 2018 always be a part of the numerator or denominator?

Numerator Denominator Can't determine

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