Find the sum of the last 17 digits of 1 0 0 ! .
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I am not understanding. How is knowing that the last digit is 0 help you with the sum?
is he asking sum or product?
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I am asking sum. If the last 24 digit of 100! is 0, then the sum of last 17 digit is definately 0.
Number of trailing zeroes in 1 0 0 ! = ⌊ 5 1 0 0 ⌋ + ⌊ 2 5 1 0 0 ⌋ = 2 4 For those unfamiliar with how I calculated the trailing number of zeroes, you may want to see the relevant wiki
Oh, I thought it was all the numbers. I said 0...00(17 0's)
We know that 100! Is equal to 1 2 3 4... 99 100 Thus no of zeroes can be determined by number of multiple of 10. Multiple of 10 are 2 5, 10, 15*4, 20... Thus there are 24 such zeroes
Sry i need to learn latex
To find number of zeroes in 100!
100/5 = 20
20/5 = 4
Total number of zeroes = 20 + 4 = 24
Yes , you are absilutely right..........
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We know the last 24 digit of 100! is 0 . So, the answer is 0.