A binary operation

It is the same as $3^4 - 4^3$ which is equal to $(3^2 \times 3^2) - (4^2 \times 4)$ so $(9 \times 9) - (16 \times 4) = 81 - 64 = 17$

Answer: $17$

3^4 -4^3

=81-64

=17

$3\bigotimes4$

$=3^4-4^3$

$=17$

3 3 3*3=81

4 4 4=64

81-64=17

3^4 - 4^3 = 81 - 64 = 17

3^4 - 4^3 = 81 - 64

81 - 64 = 17

(3^4)-(4^3)= 81-64 = 17

(3^4) - (4^3)

= 81 - 64

= 17

3^4 - 4^3 = 17

3^4-4^3=3 3 3 3-4 4*4=81-64=17

3⊗4= $3^{4}$ - $4^{3}$ =81-64=17

3X4=3^4 - 4^3=9^2 - 8^2=(9-8)(9+8)=17

a⊗b=a^b−b^a then >>> 3⊗4 means 3^4-4^3 = 17 answer is =17

3^4=81 4^3=64 81-64=17

3 x 4=3.3.3.3 - 4.4.4 3 x 4=81 - 64 3 x 4 = 17 Resultado 17

3⊗4=3^4-4^3=81-64=17 To make it clarified: The symbol (^) represents an exponent. FOR THE LONG METHOD: 3⊗4=3 3 3 3-4 4*4 =81-64 =17

3^4 * 4^3=81-64=17

3^4 - 4^3 = 81 - 64 =17

3 ⊗ 4 = 3^4 - 4^3 = 81 - 64 = 17