A binomial with a logarithm

The third term is $10{ x }^{ 3 }{ ({ x }^{ log x }) }^{ 2 }$

${ x }^{ 3+2 log{ x } }={ 10 }^{ 5 }$

$(3+2 log x) log x=5$

$(2 log x + 5)(log x - 1) = 0$

the only solution to match the restriction is $\log { x=1 }$ thus x = 10.