A big family
In a family, three of the children made the following statements:
A: I have three younger brothers.
B: I have one older sister and two younger brothers.
C: I have two older sisters and one younger brother.
What is the minimum possible number of children for all three statements to be true?
The answer is 5.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
A : I have three younger brothers.
B : I have one older sister and two younger brothers.
C : I have two older sisters and one younger brother.
The maximum number of younger brothers mentioned by any one of them is 3, while the maximum number of older sisters mentioned by any one of them is 2, so the minimum number of siblings among the 3 must be 2 + 3 = 5.
Bonus
The order of birth could be :
1) Sister A --> Brother X --> Sister B --> Brother C --> Brother Y , or
2) Sister A --> Brother B --> Sister X --> Brother C --> Brother Y , or