In the image, BDG is a rectangular triangle with side lengths of 3, 4 and 5. ABCD, DGEF and BIGH are squares.
Find x² + y².
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is there any other method than this.
Consider the diagram on the left.
sin θ = 5 3 ⟹ θ = sin − 1 ( 5 3 ) ≈ 3 6 . 8 7
β = 9 0 − 3 6 . 8 7 ≈ = 5 3 . 1 3
α = 3 6 0 − 9 0 − 3 6 . 8 7 − 9 0 ≈ 1 4 3 . 1 3
ϕ = 3 6 0 − 9 0 − 5 3 . 1 3 − 9 0 ≈ 1 2 6 . 8 7
By law of cosines, x 2 = 4 2 + 5 2 − 2 ( 4 ) ( 5 ) ( cos 1 4 3 . 1 3 ) = 7 3 ; y 2 = 3 2 + 5 2 − 2 ( 3 ) ( 5 ) ( cos 1 2 6 . 8 7 ) = 5 2 .
x 2 + y 2 = 7 3 + 5 2 = 1 2 5
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