A Bit Tricky

Calculus Level 5

f ( a , b ) = b a x 2 d x 1 x 2 f(a,b) = \int_{b}^{a}\dfrac{x^2 \, dx}{\sqrt{1-x^2}} g ( a , b ) = a b x 2 d x 1 x 2 1 g(a,b) = \int_{a}^{b}\dfrac{x^2 \, dx}{\sqrt{1-x^2}-1} If a 2 b 2 = 1 a^2-b^2 = 1 , find the value of max ( ( f + g ) ( a , b ) ) min ( ( f + g ) ( a , b ) ) . \left \lfloor \max((f+g)(a,b)) \right \rfloor- \left \lfloor \min((f+g)(a,b)) \right \rfloor \; .


The answer is 5.

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1 solution

Abhi Kumbale
Mar 24, 2016

i was just about to report the problem when i realised

brilliant +1

Rohith M.Athreya - 4 years, 6 months ago

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