Find the coefficient of x in the expansion of
( 1 − 2 x 3 + 3 x 5 ) ( 1 + x 1 ) 8
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I used Pascal's triangle to get the coefficients which is the same as the combinations you did. How did you compute the coefficients? By calculator or a by the combination formula? I realize the Pascal's triangle is inefficient when it gets large... Just curious what you did...
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Scott, the coefficient is given by ( 8 n ) as mentioned in the solution. ( n r ) (notice I have swapped the place of n ) is the combination function. Sometimes written as n C r or C r n . And it is defined as:
( n r ) = r ! ( n − r ) ! n !
So, we note that ( n r ) = ( n n − r ) . That is why the coefficients of power functions are symmetrical.
( n r ) = r ! ( n − r ) ! n ! = 1 × 2 × 3 × . . . r n ( n − 1 ) ( n − 2 ) . . . ( n − r + 1 )
Therefore,
( 8 0 ) = ( 8 8 ) = 1 -- ( n 0 ) is defined as 1 .
( 8 1 ) = ( 8 7 ) = 1 8 = 8
( 8 2 ) = ( 8 6 ) = 1 × 2 8 × 7 = 2 8
( 8 3 ) = ( 8 5 ) = 1 × 2 × 3 8 × 7 × 6 = 5 6
( 8 4 ) = 1 × 2 × 3 × 4 8 × 7 × 6 × 5 = 7 0
If you are using Microsoft Excel spreadsheet, the function is = C O M B ( n , r ) .
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f ( x ) = ( 1 − 2 x 3 + 3 x 5 ) ( 1 + x 1 ) 8 = ( 1 − 2 x 3 + 3 x 5 ) n = 0 ∑ 8 ( 8 n ) x − n
⇒ f ( x ) = ( 1 − 2 x 3 + 3 x 5 ) × ( 1 + 8 x − 1 + 2 8 x − 2 + 5 6 x − 3 + 7 0 x − 4 + 5 6 x − 5 + 2 8 x − 6 + 8 x − 7 + x − 8 )
The coefficient of x , a 1 , comes from − 2 x 3 × 2 8 x − 2 = − 5 6 x and 3 x 5 × 7 0 x − 4 = 2 1 0 x , therefore, a 1 = − 5 6 + 2 1 0 = 1 5 4 .