Powerful

Calculus Level 3

Find the minimum value of 2 ( x 2 − 3 ) 3 + 27 \large 2^{\left(x^2-3\right)^3+27} .

Answer upto 3 decimal places.


The answer is 1.000.

A Former Brilliant Member by A Former Brilliant Member

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Roger Erisman
Apr 19, 2016

x^2 >= 0 so x^2 - 3 is lowest when x^2 = 0, i.e. when x = 0

so (-3)^3 = -27 which means exponent can be no lower than -27 + 27 = 0

2^0 = 1

1 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...