A calculus problem by Dylan Scupin-Dursema

Calculus Level 2

y=x^101

Find the 102nd derivative of y.

2 0 100 101x^100 1 101! 101

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Caleb Townsend
Mar 1, 2015

In general, if a polynomial of degree n n is differentiated n n times, then by the power rule, it gives a polynomial of degree ( n n ) = 0 , (n - n) = 0, which is a constant. So if it is differentiated one more time, it will be 0 , 0, as the derivative of a constant is always 0. 0. That is, d n + 1 d x n + 1 [ P ( x ) ] = 0 \frac{d^{n+1}}{dx^{n+1}}[P(x)] = 0 if P ( x ) P(x) is a polynomial of degree n . n. In this case, n = 101 n=101 , and from the formula above, d 102 d x 102 [ x 101 ] = 0 \frac{d^{102}}{dx^{102}}[x^{101}] = \boxed{0}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...