Osculating sphere related rates

Calculus Level 4

Given the vector function r ( t ) = 2 t , t 2 , t 3 3 \vec{r}(t) = \left \langle 2t, t^2, \dfrac{t^3}{3} \right \rangle , you can get an osculating circle to r ( t ) \vec{r}(t) at any point in time t t . Use this osculating circle as the largest trace of a sphere (so now when t t changes, you have a sphere moving along the curve with its largest trace as the osculating circle to r ( t ) \vec{r}(t) ). If the rate of change of the volume of this sphere with respect to t t at t = 1 t=1 can be represented in the form A π A \pi , find A A .

Clarification:

The osculating circle to r ( t ) \vec{r}(t) at time t t is the circle tangent to r ( t ) \vec{r}(t) at time t t with radius 1 κ ( t ) \dfrac{1}{\kappa (t)} , where κ ( t ) \kappa(t) is the curvature of r ( t ) \vec{r}(t) at time t t .


The answer is 486.

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