If the linear approximation of 2 . 2 + 2 . 1 + 2 . 2 + 2 . 1 + 2 . 2 + ⋯ , using the function z = x + y + x + y + x + ⋯ and initial point ( 2 , 2 , 2 ) , is L , find 1 0 0 L .
Note:
The linear approximation to a function
z
=
f
(
x
,
y
)
at
(
x
,
y
)
is
f
(
x
,
y
)
≈
f
(
a
,
b
)
+
f
x
(
a
,
b
)
(
x
−
a
)
+
f
y
(
a
,
b
)
(
y
−
b
)
, where
(
a
,
b
,
f
(
a
,
b
)
)
is the initial point. This comes from the equation of a tangent plane, and we are using a tangent plane to find a linear approximation.
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