A geometry problem by Jade Mijares

Geometry Level 1

Find the exact numerical value of sin ( 120 ° ) cos ( 150 ° ) + cos ( 120 ° ) sin ( 150 ° ) \sin(120°)\cos(150°) + \cos(120°)\sin(150°)


The answer is -1.

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1 solution

Ramesh Goenka
Feb 3, 2015

using sin(a+b)=sin(a)cos(b) + cos(a)sin(b) where a=120 and b=150 which equals sin(270)=-1 !

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